Wednesday, March 25, 2009

Round 304

we don't have time to post the whole solution but this problem need to be solved using differential equation to get the exact answer... we probably post during the weekend...

14 comments:

Anno said...

The awnser can be obtained by doing the following:

Multiply the numer of kaus with the days they take to eat all of the grass for both of the days
then calculate the difference between those two numbers..

Calculate the difference between the days

then calculate by what factor the days have to decrease (looking from the lowest day) to reach 16

take the same factor from the calculated difference from the kau x day numbers

take that factor of the difference and part that number by the number of asked days then you should end up with a number of kaus

harutrix said...

Could the answer be 250 here's what I did. The middle represents the number added by 32. I got that by subtracting 48 from 16. The third row is the estimated. It goes by 30. You'll understand the first by looking at the question and the diagram.
2=32=30
4=64=60
6=96=90
8=128=120
10=160=160
12=192=190
14=224=220
16=256=250

Eduardo said...
This comment has been removed by the author.
chloe said...

looks like u didn factor in the growth...

RTH said...

Did anyone else try logarithms? The hint I used was "the grass grows continuously".

harutrix said...

but the thing is it that the middle is what grows. and the third represents the estimated of grass that grows.

harutrix said...
This comment has been removed by the author.
Suikin Ameboh said...

I used a simple inverted 3 rule..
something like
100 - 10
50 - 20
x - 30

bigbabybowser said...

its 168 when rounded up.

you get the answer using basic course 2 algebra. I set up 2 equations espressing the rates of which the kau ate and the grass grew.

the equations looked like this:

Let K = rate at which Kaus eat grass
Let G = rate at which grass grows
Let 1 = the fact that the field is already full of grass

1 = 48*90K - 90G
1 = 120*30K - 30G

This is a simple matter of solving linear equations. I multiplied the bottem equation by -3 getting
-3 = -360*30k + 90G
I then added the equations together to drop out the G variable.
I solved for K.
K approxis for .000617284.
Plug K in the original equation to solve for G.
G approxis for .0407407

Now that you know the rate at which grass grows and the rate 1 kaus eats grass, you can now make a new equation.
Let H = number of kaus that will eat all grass in 16 days
1 = .0098765*H - 16*.0407407

Solve for H to get 167.18 Kaus
The directions say to round up to the nearest Kaus (it says Up specifically to ignore the 4 and down rule)
Giving you 168 Kaus!

bowser said...

its 168 when rounded up.

you get the answer using basic course 2 algebra. I set up 2 equations espressing the rates of which the kau ate and the grass grew.

the equations looked like this:

Let K = rate at which Kaus eat grass
Let G = rate at which grass grows
Let 1 = the fact that the field is already full of grass

1 = 48*90K - 90G
1 = 120*30K - 30G

This is a simple matter of solving linear equations. I multiplied the bottem equation by -3 getting
-3 = -360*30k + 90G
I then added the equations together to drop out the G variable.
I solved for K.
K approxis for .000617284.
Plug K in the original equation to solve for G.
G approxis for .0407407

Now that you know the rate at which grass grows and the rate 1 kaus eats grass, you can now make a new equation.
Let H = number of kaus that will eat all grass in 16 days
1 = .0098765*H - 16*.0407407

Solve for H to get 167.18 Kaus
The directions say to round up to the nearest Kaus (it says Up specifically to ignore the 4 and down rule)
Giving you 168 Kaus!

cpsasuke_ said...

at 314,the answer is pi related.
3 is the fist number.
1+4 =5,the second number.
1+5+9=16,the third.
.
.
.
49 and 40 comes after the sequence.
49 x 40 = 1960
you can get pi at http://pi.ytmnd.com/ .
please leave the credits.

Buy Neopoints said...
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