Wednesday, June 27, 2001

Round 15

Date released: June 27th, 2001.
Date rewarded: July 6th, 2001.

Two kings of Sakhmet from history were King Galat-Ra the Lupe and King Hephaes-Ru the Kacheek. Galat-Ra died 120 years after Hephaes-Ru was born. Their combined ages when they died was 100 years. Hephaes-Ru died in the year 40 B.N. (Before Neopia).

In what year was King Galat-Ra born?

Prize


Geb

Click to show/hide solution

Let x be the year King Galat-Ra was born, y be the year King Hephaes-Ru was born. We know that: "Galat-Ra died 120 years after Hephaes-Ru was born". Therefore, Galat-Ra died in the year y + 120. His age when he died is y + 120 - x. Hephaes-Ru's age when he died is 40 B.N. - y.

We also know that: "Their combined ages when they died was 100 years." Therefore:
y + 120 - x + 40 B.N. - y = 100 <=> x = 40 B.N. + 20 = 20 B.N.

King Galat-Ra was born in 20 B.N.

Wednesday, June 20, 2001

Round 14

Date released: June 20th, 2001.
Date rewarded: June 27th, 2001.

Once again this week Richard Chia will provide you with a confusing anagram!

Hello and Welcome to the Lenny Conundrum. This weeks conundrum is a 11-letter word that has been jumbled up, can you work out what it is?



Prize


Kauvaras Potion

Click to show/hide solution

Same type of puzzle as last week. The answer is Tigersquash.

Wednesday, June 13, 2001

Round 13

Date released: June 13th, 2001.
Date rewarded: June 20th, 2001.

For this week's conundrum, I would like to pass you to my good friend Richard Chia.

Hello and Welcome to the Lenny Conundrum. This weeks conundrum is a 10-letter word that has been jumbled up, can you work out what it is?



Prize
Unknown

Click to show/hide solution

This is unscrambling puzzle type. The answer is Pterattack.

Wednesday, June 6, 2001

Round 12

Date released: June 6th, 2001.
Date rewarded: June 13th, 2001.

Mrs. Doyle the Housekeeper JubJub has made a big, big pile of sandwiches for the party of Skeiths visiting her house tonight. When she counts them, she realises that she can equally split the sandwiches between two Skeiths and have none left over. She can also split them between three Skeiths, four Skeiths, five Skeiths and six Skeiths equally and every time there will be no sandwiches left over.

What is the smallest amount of sandwiches that Mrs. Doyle could have made?


Prize
Unknown

Click to show/hide solution

The number of sandwiches is divisible by 2, 3, 4, 5 and 6. We want the find the least common multiple of the above numbers.
2 = 2
3 = 3
4 = 22
5 = 5
6 = 2 * 3

The least common multiple is:
22 * 3 * 5 = 60

Therefore, the number of sandwiches is 60.